IT1230809

Heapsort- is a much more efficient version of selection sort. It also works by determining the largest (or smallest) element of the list, placing that at the end (or beginning) of the list, then continuing with the rest of the list, but accomplishes this task efficiently by using a data structure called aheap, a special type of binary tree. Once the data list has been made into a heap, the root node is guaranteed to be the largest element. When it is removed and placed at the end of the list, the heap is rearranged so the largest element remaining moves to the root. Using the heap, finding the next largest element takes O(log n) time, instead of O(n) for a linear scan as in simple selection sort. This allows Heapsort to run in O(n log n) time.

Run-time Complexity Analysis:
It has the advantage of a worst-case Θ(n log n) runtime. It is an in-place algorithm, but is not a stable sort.

Codes:
function heapSort(a, count) is
input: an unordered array a of length count
(first place a in max-heap order)
heapify(a, count)
end := count - 1
while end > 0 do
(swap the root(maximum value) of the heap with the last element of the heap)
swap(a[end], a[0])
(decrease the size of the heap by one so that the previous max value willstay in its proper placement)
end := end - 1
(put the heap back in max-heap order)
siftDown(a, 0, end)
function heapify(a,count) is
(start is assigned the index in a of the last parent node)
start := (count - 2) / 2
while start ≥ 0 do
(sift down the node at index start to the proper place such that all nodes belowthe start index are in heap order)
siftDown(a, start, count-1)
start := start - 1
(after sifting down the root all nodes/elements are in heap order)
function siftDown(a, start, end) is
input: end represents the limit of how far down the heapto sift.
root := start
while root * 2 + 1 ≤ end do (While the root has at least one child)
child := root * 2 + 1 (root*2+1 points to the left child)
(If the child has a sibling and the child's value is less than its sibling's...)
if child + 1 ≤ end and a[child] < a[child + 1] then
child := child + 1 (... then point to the right child instead)
if a[root] < a[child] then (out of max-heap order)
swap(a[root], a[child])
root := child (repeat to continue sifting down the child now)
else
return

Application:
Comparing the array of numbers in a sorted list.

Reference:http://en.wikipedia.org/wiki/Sorting_algorithm#Heapsort